Two linear scans to figure out if its ascending or descending. If one of them works then Ordered else Unordered.

import java.io.PrintWriter;
import java.util.Scanner;

/**
 * 
 * @author Sanchit M. Bhatnagar
 * @see http://uhunt.felix-halim.net/id/74004
 * 
 */
public class Main {

  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    PrintWriter out = new PrintWriter(System.out);
    int N = sc.nextInt();
    out.println("Lumberjacks:");
    for (int i = 0; i < N; i++) {
      int[] arr = new int[10];
      for (int j = 0; j < 10; j++)
        arr[j] = sc.nextInt();

      int bad = 0;
      for (int j = 1; j < 10; j++) {
        if (arr[j - 1] > arr[j]) {
          bad++;
          break;
        }

      }

      for (int j = 1; j < 10; j++) {
        if (arr[j - 1] < arr[j]) {
          bad++;
          break;
        }
      }

      if (bad == 1) {
        out.println("Ordered");
      } else {
        out.println("Unordered");
      }
    }

    out.close();
    sc.close();
  }

}